Find the equation of the curve formed by the set of all points which are equidistant from the points A(-1, 2, 3) and B(3, 2, 1).
Consider, C(x,y,z) point equidistant from points A(-1, 2, 3) and B(3, 2, 1).
∴ AC = BC
Squaring both sides,
= 
x2 +2x + 1 + y2 -4y +4 + z2 -6z +9 = x2 -6x + 9 + y2 -4y +4 + z2 -2z +1
8x -4z = 0
Equation of curve is 8x-4z = 0
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