The probability that a person will get an electrification contract ia (2/5) and the probability that he will not get a plumbing contract is (4/7). If the probability of getting at least one contract is (2/3), what is the probability that he will get both?

Let A denote the event that a person will get electrification contract and B denote the event that the person will get a plumbing contract

Given : P(A) = , P(not B) = P() = , P(A or B) =

To find: Probability that he will get both electrification and plumbing contract = P(A and B)

Formula used : P(B) = 1 – P()

P(A or B) = P(A) + P(B) - P(A and B)

P(B) = 1 -

P(B) =

Probability of getting at least one contract =

P(A and B)

P(A and B)

P(A and B)

P(A and B)

The probability that he will get both electrification and plumbing contract =