Draw a right triangle ABC in which AB = 6 cm, BC = 8 cm and
. Draw BD perpendicular from B on AC and draw a circle passing through the points B, C and D. Construct tangents from A to this circle.

Step 1: Construct line segment AB of length 6 cm. Then construct perpendicular BC of length 8 cm. Finally join points A and C to complete the triangle.

Step 2: Construct a perpendicular from point B onto AC. Point D is where this perpendicular meets AC.

Step 3: Construct perpendicular bisector of line segment BC, which intersects it at pt. O.

Step 4: Taking centre at O and radius as OB, we construct a circle. It passes through points C and D too.

Step 5: We join points A and O.

Step 6: We construct the perpendicular bisector of AO, which intersects it at point E.

Step 7: Taking centre at E and radius as OE, we draw an arc cutting the circle at F. (We cut it at one point only because AB is already a tangent to the circle)

Step 8: We join points A and F, thus obtaining tangents AB and AF to the circle.