Draw a right triangle ABC in which AB = 6 cm, BC = 8 cm and . Draw BD perpendicular from B on AC and draw a circle passing through the points B, C and D. Construct tangents from A to this circle.



Step 1: Construct line segment AB of length 6 cm. Then construct perpendicular BC of length 8 cm. Finally join points A and C to complete the triangle.



Step 2: Construct a perpendicular from point B onto AC. Point D is where this perpendicular meets AC.



Step 3: Construct perpendicular bisector of line segment BC, which intersects it at pt. O.



Step 4: Taking centre at O and radius as OB, we construct a circle. It passes through points C and D too.



Step 5: We join points A and O.



Step 6: We construct the perpendicular bisector of AO, which intersects it at point E.



Step 7: Taking centre at E and radius as OE, we draw an arc cutting the circle at F. (We cut it at one point only because AB is already a tangent to the circle)



Step 8: We join points A and F, thus obtaining tangents AB and AF to the circle.


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