Evaluate the following integrals:
⇒
Substitute 2x-3=u
⇒ 2dx=du
⇒dx=du/2
⇒ We know that 1-cos2x=sin2x
⇒Put cosu=t
⇒-sinxdu=dt
Resubstituting the value of t=cosu and u=2x-3 we get
Now as we know cos(-x)=cosx
=
Ans: