Evaluate the following integrals:
To Find :
Now, can be written as
i.e.,
Here , let x – 2 = y dx = dy
Therefore, can be written as
Formula Used: = log |x +|+ C
Since is of the form with change in variable.
= log |y +|+ C
= log |y +|+ C
= 2 log |y +|+ C
Since , x – 2 = y and dx = dy
= 2 log |(x-2) +|+C Therefore,
= 2 log |(x - 2) +|+ C