If the sum of n terms of two arithmetic progressions are in the ratio 2n + 5 : 3n + 4, then write the ratio of their mth terms.
Let nth term of first A.P. be denoted by an
And nth term of second A.P. be denoted by an’
![]()
Now, multiplying both sides by 2 we get,
![]()
![]()

![]()
![]()
![]()
The ratio of mth term is 4m+3:6m+1