Mark the correct alternative in the following :
If the sum of odd numbered terms and the sum of even numbered terms in the expansion of 
are A and B respectively, then the value of 
is.
Given:
= A+B
= A-B
(x2-a2 )n= [(x+a)(x-a)]n
=(x+a)n (x-a)n
= (A+B) (A-B)
=A2-B2
1