Mark the Correct alternative in the following:
If tan (/4 + x) + tan (
/4 – x) = λ sec 2x, then
Given equation is
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Let us consider LHS

[ using the formulae
and
]
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[ the value of tan 45° = 1 ]
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[using the formulae cos 2x = cos2 x – sin2 x and cos2 x + sin2 x = 1]
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= 2 sec 2x
Now comparing with the LHS with RHS
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From here we can clearly say that the answer is option D.