Mark the Correct alternative in the following:
If tan (/4 + x) + tan (/4 – x) = λ sec 2x, then
Given equation is
Let us consider LHS
[ using the formulae and
]
[ the value of tan 45° = 1 ]
[using the formulae cos 2x = cos2 x – sin2 x and cos2 x + sin2 x = 1]
= 2 sec 2x
Now comparing with the LHS with RHS
From here we can clearly say that the answer is option D.