Mark the Correct alternative in the following:

The number of solutions of is

when x > 0

x² + x-1 = 1

x² + x - 2 = 0

(x-1) (x+2) = 0

x = 1, -2

when x < 0

x² - x+1 = 1

x² – x = 0

x(x-1) = 0

x = 0, 1

hence the given equation has 3 solutions and they are x = 0, 1, -1.