Mark (√) against the correct answer in the following:

The solution of the DE +

Given



Let log y = t


On differentiating we get




log t = -log (sin x) + C


log t + log(sin x) = C


log(tsin x) = C


tsin x = C


(log y)(sin x) = C


Conclusion: Therefore, (log y)(sin x) = C is the solution of

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