The pressure p and the volume V of a gas are connected by the relation, , where k is a constant. Find the percentage increase in the pressure, corresponding to a diminution of 0.5% in the volume.

Question

Philoid · Accepted Answer

Given: pv^1/4 = k

%decrease in the volume = 1/2%s

∴

pv^1/4 = k

taking log on both sides

log[pv^1/4] = log a

log P + 1.4logV = log a

Differentiating both the sides we get

⇒

Multiplying both sides by 100.

⇒

%error in P = 0.7%.