Find the point on the curve 
at which the equation of tangent is 
.
Slope of y = x – 11 is equal to 1
3x2 – 11 = 1 ⇒ x = 2 and -2
At x = 2
From the equation of curve, y = (2)3 – 11(2) + 5 = -9
From the equation of tangent, y = 2 – 11 = -9
At x = -2
From the equation of curve, y = (-2)3 – 11(-2) + 5 = 19
From the equation of tangent, y = -2 – 11 = -13
So, the final answer is (2, -9) because at x = -2, y is come different from the equation of curve and tangent which is not possible.
1