Mark (√) against the correct answer in the following:
If 
?
Given that y=sin-1(3x-4x3)
Let x=sin θ
⇒ θ=sin-1x
Then, y= sin-1(3sinθ -4sin3θ)
Using sin3θ=3sinθ -4sin3θ, we get
y=sin-1(sin3θ)=3θ=3sin-1x
Differentiating with respect to x, we get
1
Mark (√) against the correct answer in the following:
If ?
Given that y=sin-1(3x-4x3)
Let x=sin θ
⇒ θ=sin-1x
Then, y= sin-1(3sinθ -4sin3θ)
Using sin3θ=3sinθ -4sin3θ, we get
y=sin-1(sin3θ)=3θ=3sin-1x
Differentiating with respect to x, we get