Mark (√) against the correct answer in the following:
The minimum value of on [0, 3] is
Given:
f(x) = 3x4-8x3-48x+25.
F’(x) = 12x3-24x2-48 = 0
F’(x) = 12(x3-2x2-4) = 0
Differentiating again, we get,
F’’(x) = 3x2 – 4x = 0
x(3x – 4) = 0
x = 0 or x = 4/3
Putting the value in equation, we get,
f(x) = -39
Hence, C is the correct answer.