Construct an isosceles triangle whose base is 4.8 cm and whose vertical angle is 80°.


Since one of the angles is 80°, the sum of the other two will be 100°. It is isosceles. So, the other angles will be 50° and 50°.


Steps of Construction:


1. Draw a line segment AB = 4.8 cm.



2. Draw 50° angles at A and B.



3. Extend them such that they meet at C.



4. Join AC and BC.



Therefore, Δ PQR is the required isosceles triangle in which AC = BC.


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