Construct an isosceles triangle whose base is 4.8 cm and whose vertical angle is 80°.
Since one of the angles is 80°, the sum of the other two will be 100°. It is isosceles. So, the other angles will be 50° and 50°.
Steps of Construction:
1. Draw a line segment AB = 4.8 cm.

2. Draw 50° angles at A and B.

3. Extend them such that they meet at C.

4. Join AC and BC.

Therefore, Δ PQR is the required isosceles triangle in which AC = BC.