Draw a triangle ABC with side BC = 6 cm, AB=5 cm and ABC=60°. Then construct a triangle whose sides are of the corresponding sides of the triangle ABC.


ABC′ whose sides of the corresponding sides of can be drawn as follows.


Step 1 Draw a ABC with side BC = 6 cm, AB = 5 cm and ABC = .



Step 2 Draw a ray BX making an acute angle with BC on the opposite side of vertex A.



Step 3 Locate 4 points (as 4 is greater in 3 and 4), B1,B2,B3,B4 on line segment BX.


Step 4 Join B4C and draw a line through B3 , parallel to B4C intersecting BC at C′



Step 5 Draw a line through C' parallel to AC intersecting AB at A'.ABC is the required triangle.



Justification


A=60° (Common)


C=C'


By AA similarity condition



Also,


AB’=AB ,B’C’=BC and AC’=AC


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