let =


Put t=cosx


dt=-sinxdx




Putting


A(1+t)(1+2t)+B(1-t)(1+2t)+C(1-t2)=1


Putting 1+t=0


t=-1


A(0)+B(2)(1-2)+C(0)=1



Putting 1-t=0


t=1


A(2)(3)+B(0)+C(0)=1



Putting 1+2t=0





From equation(1),we get,






1
1