Find the minimum value of Z = 3x + 5y, subject to the constraints
- 2x + y ≤ 4, x + y ≥ 3, x - 2y ≤ 2, x ≥ 0 and y ≥ 0
The feasible region determined by the - 2x + y ≤ 4, x + y ≥ 3, x - 2y ≤ 2, x ≥ 0 and y ≥ 0 is given by
Here the feasible region is unbounded. The vertices of the region are A(0,4) ,B(0,3) ,C. The values of Z at the following points is
The minimum value of Z is at point C
.