Sucheta wrote a fraction whose denominator is 3 more than the numerator. Again she added 2 to the numerator and subtracted 1 from the denominator and also subtracted 1 from the numerator and added 2 with the denominator she will get two fraction whose product is . Let’s write the fraction written by Sucheta.

Question

Philoid · Accepted Answer

Let the numerator of a fraction written by Sucheta be x

Then given the denominator of the fraction is 3 more than the numerator, so the denominator = x+3

So the fraction is …..(i)

Now according to the given criteria,

she added 2 to the numerator and subtracted 1 from the denominator = …..(ii)

she subtracted 1 from the numerator and added 2 with the denominator = ……….(iii)

So Sucheta got equation (ii) and equation (iii) as two fractions.

So from question product of equation (ii) and equation (iii) is equal to ,

Hence

By cross multiplying we get

⇒ 5(x-1)=2(x+5)

⇒ 5x-5=2x+10

⇒ 5x-2x=10+5

⇒ 3x=15

From equation (i), the fraction is

Hence the fraction written by Sucheta is