A servo voltage stabilizer restricts the voltage output to 220 V ± 1%. If an electric bulb rated at 220 V, 100 W is connected to it, what will be the minimum and maximum power consumed by it?
Given,
Output voltage, V = 220 V ± 1%
= 220 V ± 2.2 V
The resistance of a bulb that is operated at voltage V and consumes power P is given by Joule’s heating effect-
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Putting the values in the above formula, we get
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(a) We know that for minimum power to be consumed, output voltage should be minimum.
The minimum output voltage will be,![]()
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The current through the bulb,![]()
Where
V is the voltage across the bulb
R is the resistance of the bulb
Putting the values in the above formula, we get
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=0.45 A
Now, the power consumed by the bulb,
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(b) For maximum power to be consumed, output voltage should be maximum.
The maximum output voltage,
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The current through the bulb,
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Power consumed by the bulb in this case is,
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