An electric bulb marked 220 V, 100 W will get fused if it is made to consume 150 W or more. What voltage fluctuation will the bulb withstand?
Given
The operating voltage is V and power consumed is P.
Therefore, the resistance of the bulb can be calculated as follows,
![]()
![]()
Putting the values in the above formula, we get
![]()
![]()
The power fluctuations is given as p = 150 W
So, the voltage fluctuation that the bulb can withstand is given by-
Resistance of the bulb, ![]()
Where
V is the velocity
P is the power fluctuations
![]()
![]()
![]()
![]()
Hence the bulb will withstand fluctuations up to 270 V.