Figure in the plot of the stopping potential versus the frequency of the light used in an experiment on photoelectric effect. Find (a) the ratio h/e and (b) the work function

from the above graph we see that,
When
=1.656V then
…… (1)
When
=0 then
…. (2)
Where
the stopping potential and ν is the frequency
Of the light.
From Einstein’s photoelectric equation,
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….(3)
∴ from eq (1) & (3) we have
….. (4)
Again from eq(2) & (3) we have
…… (5)
On solving eq (4) & (5) we get
⇒ ![]()
Work function, ![]()
Now, to find the ratio h/e we put the value of Ф
In eq (5) we get,
⇒ ![]()
⇒ ![]()
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