P 4 O 6 reacts with water according to equation P 4 O 6 + 6H 2 O → 4H 3 PO 3 . Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P 4 O 6 in H 2 O.

Question

Philoid · Accepted Answer

P₄O₆ + 6H₂O 4H₃PO₃

4H₃PO₃ + 8NaOH Na₂HPO₃ + 8H₂0

NET REACTION:

P₄O₆ + 8NaOH 4Na2HPO₃ + 2H₂O

Moles of P₄O₆ = = 0.5

Acid formed by one mole of P₄o₆ requires = 8 mol

Acid formed by 0.005 mol of NaOH is present in 100mL solution

0.04 of NaOH is present in solution = *0.04 = 400mL

P4O6 reacts with water according to equation P4O6 + 6H2O → 4H3PO3.Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.

P₄O₆ reacts with water according to equation P₄O₆ + 6H₂O → 4H₃PO₃.
Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P₄O₆ in H₂O.