Given that two numbers appearing on throwing two dice are different. Find the probability of the event, “the sum of numbers on the dice is 6”.

When two dice are thrown, there are 36 possibilities.

However, we are given, every time both dice contain different numbers means doublet is not a possibility.

As, number of doublets are 6, so, sample space, S = 36 – 6 = 30

Number of possibilities of the event when sum of dice is 6, (1, 5), (2, 4), (4, 2), (5, 1)

Here, we won’t take (3, 3) as both dice contain different numbers. So,

⇒ E = 4

So,