Arrange the following complex ions in increasing order of crystal field splitting energy Δ0.
[Cr(Cl)₆]^3–, [Cr(CN)6]^3–, [Cr(NH₃)₆]³⁺

Question

Arrange the following complex ions in increasing order of crystal field splitting energy Δ0. [Cr(Cl) 6 ] 3–, [Cr(CN)6] 3–, [Cr(NH 3 ) 6 ] 3+

Philoid · Accepted Answer

Crystal field splitting energy Δ0 increases in the order:

[Cr(Cl)₆]^3– < [Cr(NH₃)₆]³⁺ < [Cr(CN)₆]^3–

Among the ligands Cl, NH₃ and CN, Cl is the weakest ligand and CN is the strongest one. Therefore, increasing order of crystal field splitting energy Δ0 is: [Cr(Cl)₆]^3– < [Cr(NH₃)₆]³⁺ < [Cr(CN)₆]^3–

Arrange the following complex ions in increasing order of crystal field splitting energy Δ0.[Cr(Cl)6]3–, [Cr(CN)6]3–, [Cr(NH3)6]3+

Arrange the following complex ions in increasing order of crystal field splitting energy Δ0.
[Cr(Cl)₆]^3–, [Cr(CN)6]^3–, [Cr(NH₃)₆]³⁺