Activation energy of a chemical reaction can be determined by _____________.



Taking ln on both sides give: ln k= -EA/RT + lnA


The above equation has EA as activation energy and k as the rate constant.


The equation can be changed to a line equation i.e. y=mx+c, by taking log on both sides.


For two values of k at different temperatures we can get the value of EA from above Equation.


Thus option (ii) is correct.


Other options do not give an equation or values for a graph that can be plotted to find the value EA.

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