An average emf of 20 V is induced in an inductor when the current in it is changed from 2.5 A in one direction to the same value in the opposite direction in 0.1 s. Find the self-inductance of the inductor.

Question

Philoid · Accepted Answer

Given:

Emf(E) = 20 V

Rate of change of current = A/s = 50 As^-1

Formula used:

Emf , where L = self inductance, di/dt = rate of change of current

Substituting the values, we get

=> self inductance (Ans)