(a) Calculate the energy released if 238 U emits an α-particle. (b) Calculate the energy to be supplied to 238 U if two protons and two neutrons are to be emitted one by one. The atomic masses of 238 U, 234 Th and 4 He are 238.0508 u, 234.04363 u and 4.00260 u respectively.

Question

Philoid · Accepted Answer

a) [Reaction for emitting α-particle]

₂He⁴ = alpha particle

,

M_u = mass of Uranium

M_α = mass of α-particle

M_th = mass of Thorium

c²= (Speed of light)² = 931.5 MeV/u

The energy released is 4.2569 MeV

b)

M_p = mass of proton=

M_n = mass of neutron=

The energy released is 23.019 MeV

(a) Calculate the energy released if 238U emits an α-particle.(b) Calculate the energy to be supplied to 238U if two protons and two neutrons are to be emitted one by one. The atomic masses of 238U, 234Th and 4He are 238.0508 u, 234.04363 u and 4.00260 u respectively.

(a) Calculate the energy released if ²³⁸U emits an α-particle.
(b) Calculate the energy to be supplied to ²³⁸U if two protons and two neutrons are to be emitted one by one. The atomic masses of ²³⁸U, ²³⁴Th and ⁴He are 238.0508 u, 234.04363 u and 4.00260 u respectively.