Draw a right triangle in which the sides (other than the hypotenuse) are of lengths 4 cm and 3 cm. Now construct another triangle whose sides are times the corresponding sides of the given triangle.

Steps of Construction:

1. Draw a line segment BC = 3cm

2. With the help of compass, draw ∠B = 90°

3. Taking B as centre, 4cm as radius, draw an arc which intersects the ray at point A.

4. Join A to C

∴ ΔABC is the required triangle

Now, we need to make a triangle which is times its size

Steps of construction:

5. Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.

6. Mark 5 (the greater of 3 and 5 in ) points B₁, B₂, B₃, B₄, B₅ on BX so that BB₁ = B₁B₂ = B₂B₃ = B₃B₄ = B₄B₅

7. Join B₅C and draw a line through B₃ (the 3^rd point, 3 being smaller of 3 and 5 in ) parallel to B₅C, to intersect BC at C’

8. Draw a line through C’ parallel to the line AC to intersect AB at A’

Thus, A’BC’ is the required triangle.