Draw a pair of tangents to a circle of radius 3 cm, which are inclined to each other at an angle of 60°.

OR


Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 3/5 times the corresponding sides of the given triangle.



Step 1 : Draw a circle with radius 3 cm and centre O.


Step 2 : Draw any diameter AOB and Draw a radius OC such


such that BOC = 60°.



Step 3 : At C draw a perpendicular with OC and at A also


draw a perpendicular with OA.



OR


First we draw a right angle triangle


Step 1 : Draw a side AB of 4 cm with the help of scale.



Step 2 : Draw an perpendicular at point A with the help of compass. And cut 3 cm on it and named it as C.



Now we draw a triangle similar to right triangle whose sides are 3/5 times the corresponding sides.


Step 1 : Draw a line from point A below the AB.



Step 2 : Cut the line AD in 5 equal parts from point A and name them A1, A2, A3, A4, A5



Step 3 : Meet the point A5 with B and make parallel to A5B from A3.



Step 4 : Make a line parallel to BC from B1.



So, ∆ AB1C1 the required triangle whose corresponding side


is 3/5 of the right angle triangle.


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