The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is

Question

Philoid · Accepted Answer

Given a high tower whose height, AC = 150m

Angle of depression, ∠DCB = 30°

We know that alternate angles are equal.

⇒ ∠DCB = ∠ABC

Let distance of the car from tower, AB = x m

In ΔABC, tan 30°

⇒ x = 150√3

∴ The distance of car from the tower is 150√3 m.