At the equilibrium position in the process of adsorption ___________.
At equilibrium, in adsorption process, the change in free energy ΔG= 0.
We know, ΔG= ΔH – TΔS
So for ΔG= 0, ΔH= TΔS
Therefore, (ii) is correct.
In options (iii) and (iv), ΔH is not equal to TΔS. So both are wrong options.
Adsorption process at equilibrium is not accompanied with an increase in enthalpy. So (i) is not correct.