A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.


B2H6 + 2NMe → 2BH3.NMe3

A B C


3 B2H6 + 6NH3 → 3[BH3(NH3)2]+[BH4]+ → 2B3N3H6 + 12H2


A = B2H6 (DIBORANE)


B = 2BH3.NMe3 (ADDUCT)


C = 2B3N3H6 (INORGANIC BORAZINE)



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