A sparingly soluble salt having general formula Ap+x Bq-y and molar solubility S is in Equilibrium with its saturated solution. Derive a relationship between the solubility and solubility product for such salt.
A relationship between the solubility and solubility product for such salt can be derived as follows-
Let the solubility be S.
Initially, assume 1 mole of AxBy was present. From which S moles of it was dissolved to give xS and yS moles of Ap+ and Bq- respectively. This can be understood from the following equation.
Ap+x Bq-y ⇋ xA+p + yB-q
At t=0, 1 0 0
At Equilibrium, 1-S xS yS
Solubility product is the multiplication product of concentration of products each raise to their stoichiometric coefficients.
Hence, Solubility product (Ksp) = [A+p]x [B-q]y
= (xS)x(yS)y
= xxyySx+y