Consider a capacitor-charging circuit. Let Q1 be the charge given to the capacitor in a time interval of 10 ms and Q2 be the charge given in the next time interval of 10ms. Let 10μC charge be deposited in a time interval t1 and the next 10 μC charge is deposited in the next time interval t2.
Formula used :
Charge of a capacitor is given by
Charge of a capacitor, ![]()
Where
ε is the emf of a battery
C is the capacitance
R is the resistance of a resistor which is in series
T is the time period
charge developed on the capacitor in first interval of 10ms is
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charge developed on the capacitor in first interval of 20ms is
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Charge developed on the capacitor in the interval 10ms to 20ms is
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Compare
with ![]()


(Here
)
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The time taking for 10μC to developed on the plates of capacitor is ![]()
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The time taking for 10μC to developed on the plates of capacitor ![]()
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Divide (1) by (2)

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Take log on both sides
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Q1 is the charge developed on the capacitor in a time interval of 10 ms and Q2 is the charge developed on the capacitor in the next time interval of 10ms. If a10μC charge be deposited in a time interval t1 and the next 10 μC charge is deposited in the next time interval t2. Then Q1 > Q2, t1 < t2. So option B is correct.