Find the charge on the capacitor shown in figure.

Concepts/Formulas used:

Ohm’s Law:

Potential Difference (V) across a resistor of resistance R when current I passes through it is given by Ohm’s law:

Capacitance:

If two conductors have a potential difference V between the them and have charges Q and -Q respectively on them, then their capacitance is defined as

At steady state, no current passes through 6μF . Hence, we can ignore the capacitor to find the equivalent resistance.

Now, 10Ω and 20Ω are in series.

The current is given by Ohm’s law:

Now, this is the same current that passes through 10Ω resistor.

The potential across it is given by:

Now, as the capacitor is in parallel with the 10Ω resistor the,

Now,