A very long bar magnet is placed with its north pole coinciding with the centre of a circular loop carrying an electric current i. The magnetic field due to the magnet at a point on the periphery of the wore is B. The radius of the loop is a. The force on the wire is
When a bar magnet’s north pole is placed at the centre of a current carrying loop, the magnetic field will get distributed in such a way that the magnetic field will lie in the plane of the loop. So, the magnetic force will be perpendicular to the plane of the loop.

Now, let’s take a current element idl, and the magnetic field associated with it is B. Then the magnetic force on the element is,
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On integration throughout the loop of radius a,
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Or,
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Hence the force acting on the wire is 2πaiB, which is directed in the perpendicular direction of the plane of the loop.