A tangent galvanometer shows a deflection of 45° when 10 mA of current is passed through it. If the horizontal component of the earth’s magnetic field is B_H = 3.6 × 10^–5 T and radius of the coil is 10 cm, find the number of turns in the coil.

Question

Philoid · Accepted Answer

Given,

horizontal components of earth's magnetic field,

B_H =3.6 x 10^-5 T

deflection shown by the tangent galvanometer, θ = 45°

radius of coil, r = 10cm =0.1m

current through the galvanometer, I =10mA =10 x 10^-3A =10^-3A

number of turn's in the coil, n =?

n =573

A tangent galvanometer shows a deflection of 45° when 10 mA of current is passed through it. If the horizontal component of the earth’s magnetic field is BH = 3.6 × 10–5 T and radius of the coil is 10 cm, find the number of turns in the coil.