Δ f of formation of CH 4 (g) at certain temperature is –393 kJ mol –1 . The value of Δ f is

Question

Philoid · Accepted Answer

Reason: C (s) + 2H₂ (g) → CH₄ (g)

Δ_f = Δ_f + Δn_gRT

Δn_g= 1-2= -1

Substituting the value of Δn_g, above equation will become

Δ_f = Δ_f- RT

As temperature and gas constant both have a positive value, so the value of Δ_f will become more negative.

Δfof formation of CH4 (g) at certain temperature is –393 kJ mol–1. The value of Δf is