Graphically show the total work done in an expansion when the state of an ideal gas is changed reversibly and isothermally from (p i, V i ) to (p f, V f ). With the help of a PV, plot compares the work done in the above case with that carried out against a constant external pressure pf.
Consider a cylinder having 1-mole gas with no weight and no friction having area of cross-section A. Total volume is Vi and the initial pressure is p.
Let pext is the external pressure and if pext> p, piston move down until pext = p, Now the final volume is Vf. The distance moved by piston be ∆l
Therefore ∆V = ∆l × A (eq-1)
∆V = Vf - Vi
Force = pressure ×area
Therefore
F = pext× A (eq-2)
If w is work done on the system
W = force × displacement
= pext × A ×∆l
From eq-1
W = pext×(-∆V)
W = -pext∆V
W = -pext( vf – vi)
If vf> vi work is done by the system and w is negative
If vf< vi work is on the system and w is positive