Arrange the following complexes in the increasing order of conductivity of

their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2] Cl, [Co(NH3)6]Cl3 , [Cr(NH3)5Cl]Cl2



The increasing order of conductivity is as follows:


[Co(NH3)3Cl3]<[Co(NH3)4Cl2]Cl< [Cr(NH3)5Cl]Cl2<[Co(NH3)6]Cl3


These complexes have 0,1,2 and 3 free chlorine ions outside the coordination sphere respectively. More free ions not bound to a complex, greater will be the conductivity.


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