A particle starts from the origin, goes along the X-axis to the point (20 m, 0) and then returns along the same line to the point
(-20 m, 0). Find the distance and displacement of the particle during the
trip.

Let the points be O (0,0), A (20,0), B (-20,0)

Distance = OA+AB = 20+40=60 m

Displacement=0B = 20 m (negative direction)

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Question

A particle starts from the origin, goes along the X-axis to the point (20 m, 0) and then returns along the same line to the point
(-20 m, 0). Find the distance and displacement of the particle during the
trip.

Let the points be O (0,0), A (20,0), B (-20,0)

Distance = OA+AB = 20+40=60 m

Displacement=0B = 20 m (negative direction)

1

Philoid · Accepted Answer

Let the points be O (0,0), A (20,0), B (-20,0)

Distance = OA+AB = 20+40=60 m

Displacement=0B = 20 m (negative direction)