Six particles situated at the corners of a regular hexagon of side a move at a constant speed u. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other.
A regular hexagon has a side= a.
Six particles situated at the corners of the hexagon are moving with a constant speed v.
As per the question, each particle maintains a direction towards the particle at the next corner.
So, particles will meet at centroid O of triangle PQR.
Now, at any instant, the particles will form an equilateral triangle PQR with the same centroid O.
We know that P approaches Q, Q approaches R and so on.
Now, we will consider the motion of particle P. Its velocity makes an angle of
.
This component is the rate of decrease of distance PO.
Relative velocity between P and Q:
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Hence, the time taken by the particles to meet each other is
.