Calculate the tension in the string shown in figure (5-E13). The pulley and the string are light and all surfaces are frictionless. Take g = 10 m/s2.
Given:
Refer the above diagram for the FBD
T + ma =mg …(i)
And T = ma …(ii)
From equations (i) and (ii), we get:
ma + ma = mg
⇒ 2ma = g
⇒ a= =5 m/s2
From equation (ii), T = ma = 5 N