A piston is fitted in a cylindrical tube of small cross section with the other end of the tube open. The tube resonates with a tuning fork of frequency 512 Hz. The piston is gradually pulled out of the tube and it is found that a second resonance occurs when the piston is pulled out through a distance of 32.0 cm. Calculate the speed of sound in the air of the tube.

Question

Philoid · Accepted Answer

Given:
Frequency of tuning fork

Let the speed of sound in the tube be .

Let be the length at which the piston resonates for the first time and be the length at which the piston resonates for the second time.

We have:

Velocity

Hence, the speed of the sound in the tube is 328 m/s.