The light sources A, B and C emit equal amount of radiant energy per unit time. The wavelengths emitted by the three sources are 450 nm 555 nm and 700 nm respectively. The brightness sensed by an eye for the sources are XA, XB and XC respectively. Then,


Wavelength of source B is given as 555 nm. The highest luminosity is observed in source B only, because it increases from zero to 555 nm and then stars decreasing. The wavelength of source A is nearer to that of C. So, XA is greater than XC.


XB > XA, XB > XC


So, option C is correct.

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