A capacitor of 4 μ F is connected as shown in the circuit (Fig. 2.1). The internal resistance of the battery is 0.5 Ohm. The amount of charge on the capacitor plates will be

Question

Philoid · Accepted Answer

Initially the capacitor gets charged. When its charged, no current will flow through the branch with the capacitor and 10Ω resistor.

The battery has an internal resistor of 0.5Ω. Thus, the current through the 2Ω resistor will be

Since the branches AB and CD are connected in parallel, the voltage across AB and CD is same.

Voltage across CD

Voltage across AB will be only because of the capacitor because no current will flow through the resistor.

Voltage across AB