In the circuit shown in Fig. 14.5, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is

Given

Diode voltage drop = 0.3 V

Resistance R₁=5kΩ

Resistance R₂ =5kΩ

Current through the circuit i =0.2 mA

Explanation:

For the given circuit, let the voltage difference between A and B be V_AB. Then the net potential difference between A and B after including the voltage drop due to the diode will be,