is such that AB = 3 cm, BC = 2 cm and CA = 2 . 5 cm. If and EF = 4 cm, then perimeter of is


Given that ΔABC and ΔDEF are similar triangles such that AB = 3 cm, BC = 2 cm, CA = 2.5 cm and EF = 4 cm.


We know that two triangles are similar if their corresponding sides are proportional.



First consider,




DE = 6 cm … (1)


Now,




DF = 5 cm … (2)


Then, perimeter of ΔDEF = DE + EF + DF = 6 + 4 + 5


Perimeter of ΔDEF = 15 cm

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