If ABC and DEF are similar triangles such that = 47° and
= 83°, then
=
Given ABC and DEF are two similar triangles, ∠A = 47° and ∠E = 83°
We know that SAS similarity criterion states that if one angle of a triangle is equal to one angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar.
In ΔABC and ΔDEF,
if and ∠A = ∠D, then ΔABC ~ ΔDEF
So, ∠A = ∠D
⇒ ∠D = 47° … (1)
Similarly, ∠B = ∠E
⇒ ∠B = 83° … (2)
We know that the sum of all angles of a triangle is equal to 180°.
⇒ ∠A + ∠B + ∠C = 180°
⇒ 47° + 83° + ∠C = 180°
⇒ 130° + ∠C = 180°
⇒ ∠C = 180° - 130° = 50°
∴ ∠C = 50°